Section 2.1 Overview (Angus)
¶Subsection 2.1.1 Belyi morphisms
Let \(X\) be an algebraic curve over \(\CC\) (i.e. a compact Riemann surface) when is \(X\) defined over \(\overline \QQ\text{?}\)
Theorem 2.1.1. Belyi.
An algebraic curve \(X/\CC\) is defined over \(\overline \QQ \iff\) there exists a morphism \(\beta \colon X \to \PP^1 \CC\) ramified only over \(\{0,1,\infty\}\text{.}\)
Definition 2.1.2. Ramified.
(AG) A morphism \(f \colon X \to Y\) is ramified at \(x \in X\) if on local rings the induced map \(f^\# \colon \sheaf O_{Y,f(x)} \to \sheaf O_{X,x}\) descended to
is not a finite separable field extension.
(RS) A morphism \(f \colon X \to Y\) is ramified at \(x \in X\) if there are charts around \(x\) and \(f(x)\) such that \(f(x) = x^n\text{.}\) This \(n\) is the ramification index.
Definition 2.1.3. Belyi morphisms.
A Belyi morphism is one ramified only over \(\{0,1,\infty\}\)
A clean Belyi morphism or pure Belyi morphism is a Belyi morphism where the ramification indices over 1 are all exactly 2.
Lemma 2.1.4.
A curve \(X\) admits a Belyi morphism iff it admits a clean Belyi morphism.
Proof.
If \(\alpha \colon X\to \PP^1 \CC\) is Belyi, then \(\beta = 4\alpha(1-\alpha)\) is a clean Belyi morphism.
Subsection 2.1.2 Dessin d'Enfants
Definition 2.1.5.
A dessin d'Enfant (or Grothendieck Dessin or just Dessin) is a triple \((X_0,X_1,X_2)\) where \(X_2\) is a compact Riemann surface, \(X_1\) is a graph, \(X_0 \subset X_1\) is a finite set of points, where \(X_2 \smallsetminus X_1\) is a collection of open cells. \(X_1 \smallsetminus X_0\) is a disjoint union of line segments
Lemma 2.1.6.
The data of a dessin is equivalent to a graph with an ordering on the edges coming out of each vertex.
Definition 2.1.7. Clean dessins.
A clean dessin is a dessin with a colouring (white and black) on the vertices such that adjacent vertices do not share a colour.
Subsection 2.1.3 The Grothendieck correspondence
Given a Belyi morphism \(\beta\colon X \to \PP^1 \CC\) the graph \(\beta^{-1}(\lb 0,1\rb)\) defines a dessin.
Theorem 2.1.8.
The map
is a bijection up to isomorphisms.
Example 2.1.9.
Subsection 2.1.4 Covering spaces and Galois groups
A Belyi morphism defines a covering map.
the coverings are controlled by the profinite completion of
Theorem 2.1.10.
There is a faithful action
Proof.
By Belyi's theorem every elliptic curve \(E/\overline \QQ\) admits a Belyi morphism. For each \(j \in \overline\QQ\) there exists an elliptic curve \(E_j/\overline \QQ\) with \(j\)-invariant \(j\text{.}\)
Given \(\sigma \in \absgal{\QQ}\text{,}\)
assume \(\sigma \mapsto 1\text{,}\)
a contradiction.
Corollary 2.1.11.
We have a faithful action of \(\absgal{\QQ}\) on dessins.
Theorem 2.1.12.
We have a faithful action of \(\absgal{\QQ}\) on the set of dessins of any fixed genus.
Subsection 2.1.5 Exercises
Exercise 2.1.13.
Compute the Dessins for the following Belyi morphisms
- \begin{equation*} \PP^1\CC\to \PP^1\CC,\,x\mapsto x^4 \end{equation*}
- \begin{equation*} \PP^1\CC\to \PP^1\CC,\,x\mapsto x^2(3-2x) \end{equation*}
- \begin{equation*} \PP^1\CC\to \PP^1\CC,\,x\mapsto \frac{1}{x(2-x)} \end{equation*}
Exercise 2.1.14.
Give an alternate proof of the fact that \(X\) admits a Belyi morphism if and only if it admits a clean Belyi morphism using dessins and the Grothendieck correspondence.
Exercise 2.1.15.
Prove that a Belyi morphism corresponding to a tree, that sends \(\infty\) to \(\infty\) is a polynomial.