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Section 8.1 CM abelian varieties

Let \(k\) be a field.

Recall that an abelian variety is a proper group variety over \(k\text{.}\) Let \(A/k\) be an abelian variety.

Definition 8.1.1. Endomorphism algebra.

The endomorphism ring of \(A\) is the ring of all isogenies \(A \to A\)

\begin{equation*} \End(A) = \Hom_{k-isog}(A,A) \end{equation*}

the endomorphism algebra is

\begin{equation*} \End^0(A) = \End(A) \otimes \QQ \end{equation*}

this is a possibly non-commutative semisimple \(\QQ\)-alg.

for a semisimple algebra the reduced degree is defined by decomposing

\begin{equation*} B = \prod B_i \end{equation*}

simple algebras with center \(k_i\text{.}\)

\begin{equation*} [B: k]_{\mathrm{red}}=\sum_{i}\left[B_{i}: k_{i}\right]^{1 / 2} \cdot\left[k_{i}: k\right] \end{equation*}

We can bound the dimension of this algebra by observing that it acts faithfully on the homology / tate module for \(\ell \ne \characteristic k\text{,}\) these are dimension \(2\dim A\)). With Artin-Wedderburn this gives

\begin{equation*} 2\dim A \ge [ \End^0(A) : \QQ] _{red} \ge [ E:\QQ] \end{equation*}

for any etale algebra \(E\) in \(\End^0(A)\text{.}\)

If the first inequality is an equality they both are and we say that \(A\) has CM. In this case \(\End^0(A)\) is a product of matrix algebras over fields.

Example 8.1.2. Elliptic curves.

We have several possibilities

  1. \begin{equation*} A\colon y^2+ y = x^3- x^2/\QQ \end{equation*}
    has \(\End^0(A)= \QQ\text{,}\) dim \(\sqrt 1 \cdot 1 \le 2\) no CM
  2. \begin{equation*} A\colon y^2 = x^3+ 1/\QQ(\zeta _3) \end{equation*}
    has \(\End^0(A)= \QQ(\zeta _3)\text{,}\) dim \(\sqrt 1 \cdot 2 \le 2\text{,}\) CM, own maximal etale.
  3. \begin{equation*} A\colon y^2 + y = x^3 + x^2 +x + 1/\FF_4 \end{equation*}
    we can find 24 automorphisms, that make the group \(\SL_2(\FF_3)\text{.}\) And \(\End^0(A)\) is the quaternion algebra \(\QQ\) ramified at \(2,\infty \text{.}\) So
    \begin{equation*} [\End^0(A) : \QQ]_{red} = \sqrt 4 \cdot 1 = 2 \end{equation*}
    here the maximal etale algebras inside are the imaginary quadratic fields contained in this quaternion algebra.
    \begin{equation*} \left(\frac{-1,-1}{\QQ}\right) \end{equation*}
  4. The same example over \(\FF_2\text{,}\) of the 24 automorphisms only 2 are defined over \(\FF_2\text{,}\) and we have
    \begin{equation*} \End^0(A) = \QQ(\sqrt{-2}) \end{equation*}
    \begin{equation*} [\End^0(A) : \QQ]_{red} = \sqrt 1 \cdot 2 = 2 \end{equation*}
    so CM again with one of the same etale algebras \(E\) as before.
  5. Given a CM elliptic curve \(A/\QQ\) with CM by \(F\) can take the product
    \begin{equation*} A \times A / k \end{equation*}
    this has dimension two and
    \begin{equation*} \End^0(A) = \Mat_{2\times 2}(F) \end{equation*}
    this is a 4-dim algebra over its center of dim 2
    \begin{equation*} \sqrt 4 \cdot 2 = 4 = 2 \dim A \end{equation*}
    etale algebra
    \begin{equation*} E = F \times F\text{.} \end{equation*}
  6. Given non-isogenous CM elliptic curves \(A,A'/\QQ\) with CM by \(F,F'\) can take the product
    \begin{equation*} A \times A' / k \end{equation*}
    this has dimension two and
    \begin{equation*} \End^0(A) = F \times F' \end{equation*}
    this is a product of two 1-dimensional algebras over their centers
    \begin{equation*} \sqrt 1 \cdot 2 +\sqrt 1 \cdot 2 = 4 = 2 \dim A \end{equation*}
    etale algebra
    \begin{equation*} E = F \times F'\text{.} \end{equation*}

Subsection 8.1.1 Construction over \(\CC\)

We can construct many examples over \(\CC\) as follows.

Definition 8.1.3. CM-pairs.

A CM-pair is a pair

\begin{equation*} E, \Phi \end{equation*}

where \(E\) is a product of CM fields (aka a CM-algebra). Such an algebra has an involution

\begin{equation*} \iota _E \colon E\to E \end{equation*}

non-trivial on each field such that for any embedding

\begin{equation*} \phi \in \Hom(E, \CC) \end{equation*}
\begin{equation*} \phi \circ \iota _E = \bar \cdot \circ \phi \text{.} \end{equation*}

\(\Phi \) is a CM-type

\begin{equation*} \Phi \subset \Hom(E, \CC) \end{equation*}

of cardinality \(\dim E/2\) s.t

\begin{equation*} \iota _E \Phi \cup \Phi = \Hom(E, \CC)\text{.} \end{equation*}

Given such a CM-pair and a choice of lattice

\begin{equation*} \Lambda \subseteq E \end{equation*}

we can form a complex torus

\begin{equation*} \CC^\Phi / \Phi (\Lambda )\text{.} \end{equation*}

To make this into an abelian variety we need the existence of a polarization. The relevant Riemann forms are given by

\begin{equation*} E\times E \to \QQ \end{equation*}
\begin{equation*} (x,y ) \mapsto \trace_{E/\QQ}(\alpha x \iota _E( y)) \end{equation*}

for \(\alpha \in E^\times\) satisfying

\begin{equation*} \iota _E \alpha = -\alpha \end{equation*}
\begin{equation*} \im(\phi (\alpha )) \gt 0,\,\forall \phi \in \Phi \text{.} \end{equation*}

So we can make a choice of \(\alpha \) and obtain an abelian variety in this way. Such abelian varieties have CM as

\begin{equation*} \End^0(A) \end{equation*}

contains etale algebra \(E\) which has dimension \(2 \cdot \# \Phi = 2 \dim A\text{.}\)

Over \(\CC\text{:}\) A simple abelian variety has CM iff \(\End^0(A)\) is a field of dimension \(2 \dim A\text{,}\) moreover such a field is necessarily a CM field.

(Sketch) Full faithfulness follows from: The torsion points are algebraic and Zariski dense. For essential image take \(A\) we can find \(A' /k\) with same CM-type by spreading out type stuff, so \(A'_\CC\) is isogenous to the original. Now the kernel of the isogeny is algebraic again so can quotient by it in both categories.

So CM abvars \(/k\) are equivalent to CM abvars \(/\CC\text{.}\)

Using Neron(-Ogg-Shafarevich) we get

Let \(A\) be an abelian variety with complex multiplication by $E$ over a field $k,$ and let $\mathfrak{a}$ be a lattice ideal in $R .$ A surjective homomorphism $\lambda^{\mathfrak{a}}: A \rightarrow A^{\mathfrak{a}}$ is an a-multiplication if every homomorphism $a: A \rightarrow A$ with $a \in \mathfrak{a}$ factors through $\lambda^{\mathfrak{a}},$ and $\lambda^{\mathfrak{a}}$ is universal for this property, in the sense that, for every surjective homomorphism $\lambda^{\prime}: A \rightarrow A^{\prime}$